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15 August, 03:56

Jim has calculated the area of a rectangle to be x^3 + x^2 + x + 1. If the width of the rectangle is x + 1, then its length is

A) x^2 + 1

B) x^2 + x + 1

C) x^3 + x^2

D) x^3 + x^2 + x

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  1. 15 August, 06:16
    0
    A = x^3 + x^2 + x + 1

    A = x^2 (x + 1) + (x+1)

    A = (X + 1) (x^2 + 1)

    W = x + 1

    so L = x^2 + 1 because A = L*W

    answer

    A) x^2 + 1
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