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11 February, 23:05

Sharon is paving a rectangular concrete driveway on the side of her house. The area of the driveway is 5x^2 + 43x - 18, and the length of the driveway is x + 9.

Additionally, Sharon plans to install a carport over a small portion of the driveway. The volume that the carport can enclose is 48x^3 + 68x^2 - 8x - 3, and the area of driveway beneath the carport is 8x^2 + 10x - 3.

Determine the width of the entire driveway and height of the carport in terms of x. Replace the values of m and b to complete the expression that represents the width of the entire driveway on the first line, and then replace the values of m and b to complete the expression that represents the height of the carport on the second line.

You have to type the answer in mx+b

im just trying to graduate ...

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  1. 12 February, 02:39
    0
    The width of the driveway is 5x-2.

    The height of the carport is 6x+1.

    We complete polynomial long division for both of these.

    For the driveway:

    Dividing 5x²+43x-18 by x+9, we first see how many times x will go into 5x². It goes in 5x times; we write this in the division problem above 43x. Multiplying back through,

    5x (x+9) = 5x²+45x. This goes below 5x²+43x. We now subtract:

    5x²+43x - (5x²+45x) = - 2x; this goes below the 45x we wrote earlier. Bring down the - 18.

    Now we see how many times x goes into - 2x; it goes - 2 times. This goes beside our 5x in our answer at the top. Multiplying back through,

    -2 (x+9) = - 2x-18. This goes below our - 2x-18 we had, and gives us an answer of 5x-2 with a remainder of 0.

    For the carport:

    To divide 48x³+68x²-8x-3 by 8x²+10x-3, we see how many times 8x² will go into 48x³. It will go 6x times; write this above - 8x. Multiplying back through,

    6x (8x²+10x-3) = 48x³+60x²-18; write this below 48x³+68x²-8x. Now subtract:

    48x³+68x²-8x - (48x³+60x²-18) = 8x²+10x; this goes below our 48x³+60x²-18. Bring down the - 3.

    Now we want to see how many times 8x² will go into 8x². It goes 1 time; write this beside our 6x at the top. Multiplying back through,

    1 (8x²+10x-3) = 8x²+10x-3; write this below the 8x²+10x-3 we have already down. When we subtract these, we get a remainder of 0, with our answer up top as 6x+1.
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