Ask Question
5 September, 17:41

John Jogger purchased a three-year membership at a local fitness center at the beginning of the year. It cost him $395 per year. He goes twice a week for the first three months (13 weeks) of the year, but then goes only twice a month for the rest of the year.

If he repeats this pattern each year, how much does each visit to the center cost?

$ A.) $2.99 or B.) $8.98 per visit.

If he continued going twice a week all year, how much would each visit cost?

$ A.) 3.80 or B.) $1.27 per visit.

+4
Answers (1)
  1. 5 September, 20:08
    0
    1. We need to find how many times John Jogger went to the gym.

    He goes 2x weekly for 13 weeks.

    13 x 2 = 26 times in the first 3 months.

    We still have another 9 months left. He goes twice monthly for each month.

    9 x 2 = 18.

    We add the total times he went to the gym for the first 3 months to the other 9 months in the year.

    26 + 18 = 44 times in one year. If we repeat this for 3 years, you get 44 x 3 = 132 gym visits in three years.

    The gym membership is $395 per year. For three years this is 395 x 3 = $1185.

    He went to the gym 132 times for a total of $1185. To find the price per visit, divide the total price by the amount of times he went to the gym.

    1185/132 = ~$8.98 per gym visit.

    2. If 13 weeks = 3 months (1/4 of a year), then there are 52 weeks per year.

    If he goes twice every week for 52 weeks, that's 52 x 2 = 104 times per year. If he kept this up for three years, that's 104 x 3 = 312 gym visits in three years.

    At the price we found earlier of $1185 for a three-year membership, divide the price by the total number of visits to find the price per visit.

    1185/312 = ~$3.80 per gym visit.
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “John Jogger purchased a three-year membership at a local fitness center at the beginning of the year. It cost him $395 per year. He goes ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers