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15 September, 20:04

A 2.25g bullet imbeds itself in a 1.50-kg block, which is attatched to a spring of force constant 785N/m. If the maximum compression of the spring is 5.88cm, find (a) the initial speed of the bullet and (b) the time for the bullet block system to come to rest.

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  1. 15 September, 23:34
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    first find the block's velocity after the collision occurs.

    1/2 (1.5 + 0.00225) V^2 = 1/2 (785) (0.0588) ^2

    so V = 1.344 m/s

    using conservation of momentum we get:

    (mv) bullet + 0 = (1.50225) (1.344)

    0.00225 v = 2.02

    v = 2.02 / 0.00225 = 897.3 m/s

    Using distance = average velocity * time t = 0.0588 / (1.344/2) = 0.0875 s
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