A firecracker shoots up from a hill 150 feet high, with an initial speed of 110 feet per second. Using the formula H (t) = - 16t2 + vt + s, approximately how long will it take the firecracker to hit the ground?

Eight seconds

Nine seconds

10 seconds

11 seconds

Question

Mathematics

Elian

13 February, 10:01

A firecracker shoots up from a hill 150 feet high, with an initial speed of 110 feet per second. Using the formula H (t) = - 16t2 + vt + s, approximately how long will it take the firecracker to hit the ground?

Eight seconds

Nine seconds

10 seconds

11 seconds

+5

Answers (1)

Know the Answer?

Kadin · Answer 1

The correct answer for the question that is being presented above is this one: "Nine seconds." A firecracker shoots up from a hill 150 feet high, with an initial speed of 110 feet per second. Using the formula H (t) = - 16t2 + vt + s, approximately the firecracker will hit the ground in Nine seconds

A firecracker shoots up from a hill 150 feet high, with an initial speed of 110 feet per second. Using the formula H (t) = - 16t2 + vt + s, approximately how long will it take the firecracker to hit the ground?Eight secondsNine seconds10 seconds11 seconds

A firecracker shoots up from a hill 150 feet high, with an initial speed of 110 feet per second. Using the formula H (t) = - 16t2 + vt + s, approximately how long will it take the firecracker to hit the ground?

Eight seconds

Nine seconds

10 seconds

11 seconds