Ask Question
30 May, 12:03

Sin 70°cos 10°-cos 70°sin 10=√3/2

+1
Answers (1)
  1. 30 May, 13:22
    0
    Let a = 70° and b = 10° (and a-b=70-10 = 60)

    We have the following trigonometric identity:

    sin (a-b) = sin (a). cos (b) - sin (b). cos (a) OR:

    sin (70-10) = sin70. cos10 - sin10. cos70

    But sin (70-10) = sin (60) and we know that sin (60°) = (√3) / 2
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Sin 70°cos 10°-cos 70°sin 10=√3/2 ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers