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5 August, 21:06

The Math Club is sponsoring a bake sale. If their goal is to raise at least $300, how many pies must they sell at $6.00 each in order to meet that goal? Write, solve, and graph an inequality that represents this situation.

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  1. 5 August, 23:07
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    Inequality: 6x ≤ 300 solution: x ≤ 50 (at least 50 pies must be sold)

    x = number of pies

    6x ≤ 300

    /6 / 6

    x ≤ 50
  2. 5 August, 23:47
    0
    Given:

    bake sale at least $300

    price of each pie is $6.00

    let the number of pies be represented by x.

    Write the inequality:

    6x > 300

    Solve the inequality:

    6x > 300

    :6 : 6

    x > 50

    Graph the inequality.

    y = 6x

    x is the number of pies sold; x at least 50 and gradually increases.

    y is the total sales
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