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4 August, 13:54

A flyer on a reconnaissance flight has 4 hours for a round trip. his blade can fly 200 mph in still air. he flies out from his base against a 20 mph wind and immediately returns to his base, flying with the same wind. how many hours did he take for his fight out?

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  1. 4 August, 14:09
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    When flying with the wind, the effective plane speed is 200 + 20 = 220 mph.

    When flying against the wind, the effective plane speed is 200 - 10 = 180 mph.

    Let d = the distance (miles) from his base to the destination.

    The time (hours) to travel with the wind is

    t₁ = d/220

    The time (hours) to travel against the wind is

    t₂ = d/180

    The total time taken is 4 hours, therefore

    t₁ + t₂ = 4

    d/220 + d/180 = 4

    d (1/220 + 1/180) = 4

    0.010101d = 4

    d = 396 miles

    Therefore

    t₁ = 396/220 = 1.8 hours = 1 hour, 48 minutes (floght in)

    t₂ = 396/180 = 2.2 hours = 2 hours, 12 minutes (flight out)

    Answer: 2.2 hours
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