A flyer on a reconnaissance flight has 4 hours for a round trip. his blade can fly 200 mph in still air. he flies out from his base against a 20 mph wind and immediately returns to his base, flying with the same wind. how many hours did he take for his fight out?

When flying with the wind, the effective plane speed is 200 + 20 = 220 mph.

When flying against the wind, the effective plane speed is 200 - 10 = 180 mph.

Let d = the distance (miles) from his base to the destination.

The time (hours) to travel with the wind is

t₁ = d/220

The time (hours) to travel against the wind is

t₂ = d/180

The total time taken is 4 hours, therefore

t₁ + t₂ = 4

d/220 + d/180 = 4

d (1/220 + 1/180) = 4

0.010101d = 4

d = 396 miles

Therefore

t₁ = 396/220 = 1.8 hours = 1 hour, 48 minutes (floght in)

t₂ = 396/180 = 2.2 hours = 2 hours, 12 minutes (flight out)

Answer: 2.2 hours