A.) What is the exact surface area of the container with a radius of 9 in and a height of 36 in?

It could be a cylinder

I will put the SA formula for btoh

SAcylinder=2pir^2+2hpir

2pir^2=2 bases

2hpir=around area

r=9

h=36

SA=2pi9^2+2*36pi*9

SA=2pi81+72pi9

SA=162pi+648pi

SA=810pi

aprox pi=3.141592

SA=2544.68952 in^2

R = 9

h = 36

Pp = ? area of a circle

l = ? surface of the wheel

Pb = lateral surface

Pc - total surface

Pp = πr² = 9²*π = 81π (unit²)

l = 2πr = 2*9*π = 18π (unit)

Pb = l*h = 18π * 36 = 648 π (unit²)

Pc = 2Pp + Pb = 2 * 81π + 648π = 162π + 648π = 810π (unit²)

Answer total area equal to 810π (unit²)