Find the value of the polynomial 2x^3y^3+3xy-3x^3y^3+x^2y-xy+2x^2y, for x=-1 and y=2.

Answer: 10

Step-by-step explanation:

2x³y³ + 3xy - 3x³y³ + x²y - xy + 2x²y, where x = - 1 and y = 2

Now substitute for x and y in the expression above.

2 (-1) ³ (2) ³ + 3 (-1) (2) - 3 (-1) ³ (2) ³ + (-1) ² (2) - (-1) (2) + 2 (-1) ² (2)

(-2) (8) + (-3) (2) + 3 (8) + (1) (2) + (1) (2) + 2 (1) (2)

= - 16 - 6 + 24 + 2 + 2 + 4

= - 22 + 32

= 10