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13 April, 08:27

the perimeter of a rectangle field is 118m. if the length of the rectangle is 7m less than twice the width what is the length

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Answers (2)
  1. 13 April, 08:42
    0
    w = 22 l = 37

    Explanation:

    Perimeter = P

    Length = l

    Width = w

    Formula: P = 2 (w + l) + 2w

    We know

    P = 118

    l = 2w - 7

    Solve

    P = 2 (2w - 7) + 2w

    118 = 4w - 14 + 2w

    118 = 6w - 14

    +14 + 14

    132 = 6w

    6 6

    w = 22

    2 (22) - 7

    44 - 7 = 37

    l = 37
  2. 13 April, 09:21
    0
    Let:

    P - perimeter

    l - length

    w - width

    We know:

    P = 118 m

    l = 2w - 7

    Rectangle perimeter's formula: P = 2l + 2w

    We replace the length with 2w - 7.

    P = 2 * (2w - 7) + 2w

    118 = 4w - 14 + 2w

    118 = 6w - 14

    6w = 118 + 14

    6w = 132

    w = 22 meters
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