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4 June, 05:41

In order to determine the average price of hotel rooms in Atlanta. Using a 0.1 level of significance, we would like to test whether or not the average room price is significantly different from $110. The population standard deviation is known to be $16. A sample of 64 hotels was selected. The p-value associated with the test statistic (z) is calculated and it is 0.12.

We conclude that the average price of hotel rooms in Atlanta is NOT significantly different from $110. (Enter 1 if the conclusion is correct. Enter 0 if the conclusion is wrong.)

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  1. 4 June, 06:47
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    Step-by-step explanation:

    Normal distribution

    size sample = 64

    Standard deviation : 16

    We have z (s) = 0,12

    By definition

    z (s) = [ (X - μ₀) / (σ/√) ⇒ 0,12 = (X - 110) / (16/√64 0,12 = (X-110) * √64/16

    0.12 * 16 = (8*X - 110*8) ⇒ 1.92 + 880 = 8*X

    X = 110,24
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