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31 May, 14:28

Suppose that a customer is purchasing a car. He conducts an experiment in which he puts 10 gallons of gas in the car and drives it until it runs out of gas. Be conducted this experiment 15 times on each car and records the number of miles driven.

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  1. 31 May, 17:30
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    Question Continuation:

    Car 1, Car 2

    227,240

    209,237

    237,212

    229,227

    209,251

    261,159

    251,208

    251,260

    282,169

    250,269

    254,296

    254,312

    271,307

    259,287

    262,277

    What is the sample mean for car 1 and 2?

    What is the median of car 1 and 2?

    Answer:

    Car 1

    Mean = 247.067, Median = 251

    Car 2

    Mean = 247.4, Median = 251

    Step-by-step explanation:

    Given

    N = Number of Observation = 15

    Mean = Summation of Observation/N

    For Car 1;

    Mean = (227 + 209 + 237 + 229 + 209 + 261 + 251 + 251 + 282 + 250 + 254 + 254 + 271 + 259 + 262) / 15

    Mean = 3706/15

    Mean = 247.067

    For Car 2;

    Mean =

    (240 + 237 + 212 + 227 + 251 + 159 + 208 + 260 + 169 + 269 + 296 + 312 + 307 + 287 + 277) / 15

    Mean = 3711/15

    Mean = 247.4

    Calculating Median

    For Car 1;

    First, we arrange the numbers in ascending order;

    209, 209, 227, 229, 237, 250, 251, 251, 254, 254, 259, 261, 262, 271, 282

    The are odd number of observations.

    Median = 15/2 = 8th position.

    The observation at the 8th position is 251

    For Car 2

    159, 169, 208, 212, 227, 237, 240, 251, 260, 269, 277, 287 296, 307, 312

    The are odd number of observations.

    Median = 15/2 = 8th position.

    The observation at the 8th position is 251
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