In a game of shuffleboard (played on a horizontal surface), a puck is given an initial speed of 6.00 m/s. It slides a distance of 9.00 m before coming to rest. What is the coefficient of kinetic friction between the puck and the surface? Write the answer with 2 decimal places

about 0.20

Step-by-step explanation:

The speed, acceleration, and distance satisfy the equation ...

v² = 2ad

So the acceleration is ...

a = v² / (2d) = (6 m/s) ² / (2*9 m) = 2 m/s²

If we take the acceleration due to gravity to be 9.8 m/s², the coefficient of kinetic friction is the ratio of these:

k = (2 m/s²) / (9.8 m/s²) ≈ 0.20