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Mathematics
Axle
7 March, 10:35
2x + 5y = - 3
2x + 2y = 6
+3
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2
)
Shrinkwrap
7 March, 12:28
0
Answer: x = 6 and y = - 3
Step-by-step explanation: What we have in this question is a pair of simultaneous equations,
2x + 5y = - 3 - - - (1)
2x + 2y = 6 - - - (2)
We shall use the elimination method to solve this since none of the variables has a coefficient of 1. We multiply equation (1) by 2 and multiply equation (2) by 5 {to eliminate the y variable). So we now have,
2x + 5y = - 3 - - - x2
2x + 2y = 6 - - - x5
4x + 10y = - 6 - - - (3)
10x + 10y = 30 - - (4)
Subtract equation (3) from equation (4)
10x - 4x + (10y - 10y) = 30 - (-6)
6x = 30 + 6
6x = 36
Divide both sides of the equation by 6
x = 6
Having calculated that x = 6, substitute for the value of x into equation (1)
2x + 5y = - 3
2 (6) + 5y = - 3
12 + 5y = - 3
Subtract 12 from both sides of the equation
5y = - 3 - 12
5y = - 15
Divide both sides of the equation by 5
y = - 3
Therefore x equals 6 and y equals - 3
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Isabella
7 March, 13:55
0
(6, - 3)
Step-by-step explanation:
Given the 2 equations
2x + 5y = - 3 → (1)
2x + 2y = 6 → (2)
Subtracting (1) from (2) term by term will eliminate the x - term
(2x - 2x) + (2y - 5y) = 6 - ( - 3), that is
- 3y = 9 (divide both sides by - 3)
y = - 3
Substitute y = - 3 in either of the 2 equations and solve for x
Substituting y = - 3 in (1)
2x + 5 ( - 3) = - 3
2x - 15 = - 3 (add 15 to both sides)
2x = 12 (divide both sides by 2)
x = 6
Solution is (6, - 3)
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