Will, Sue and Micah went to dinner. Will paid 1/4 of the bill. Micah and Sue paid in the ratio of 1:3. If Sue paid $15 more than Will, how much did dinner cost in total?

The dinner cost was $ 48

Step-by-step explanation:

Let the dinner cost was $ x

Will paid x / 4

Micah paid 1 / 4 of remaining (1 - 1 / 4) x = 3/4 x

i. e

4 / 16x

Sue paid 3/4 of remaining (1 - 1 / 4) x = 3/4x

i. e

9/16 x

Sue paid $ 15 more than Will.

∴ 9/16 x - 1 / 4 x = 5/16x=15

or

x=$48

Will paid 48 / 4 = $ 1 2, Miah paid 4 / 16. 48 = $ 12

, Sue paid 9/16⋅ 48 = $ 27

The dinner cost was $ 48

.