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23 February, 11:06

Word problem on direct variation

moving object, the force acting on the object varies directly with the object's acceleration. When a force of 100 N acts on a certain object, the accelerati

object is 10 m/s. If the force is changed to 90 N, what will be the acceleration of the object?

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  1. 23 February, 12:00
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    acceleration would be 9 meters per second squared

    Step-by-step explanation:

    If quantity "A" varies directly with quantity "B", then we can write:

    A = kB

    Now, this problem says that force (f) varies directly with acceleration (a). So we can write:

    f = ka

    Given f = 100 and a = 10, so we substitute and find k (the proportionality constant). Shown below:

    f = ka

    100 = k (10)

    k = 100/10

    k = 10

    So, we have

    f = 10a

    Now, force is 90, so what's the acceleration?

    90 = 10a

    a = 90/10

    a = 9

    So, the acceleration would be 9 meters per second squared
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