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26 April, 02:59

Bus stop Restaurant sell 3/4 as many cheeseburgers as they do with hamburgers on any given day. If there are a total of 42 burgers sold, how many hamburgers sold

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  1. 26 April, 03:58
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    24cb 18 hb

    Step-by-step explanation:

    Let's call C the number of cheese burger sold and H the number of hamburgers.

    As the cheeseburger sold are 3/4 of hamburgers, we can represent with the following equation:

    C = (3/4) H (equation 1)

    The total of burgers sold are the total of cheeseburger plus the total of hamburgers, and the sum 42. The equation representing it is:

    C + H = 42

    Replacing C by its value of eq. 1:

    (3/4) H + H = 42

    (3/4) H + (4/4) H = 42

    (7/4) H = 42

    Dividing both sides by (7/4)

    H = 42 / (7/4)

    H = 42 * (4/7)

    H = (42/7) * 4

    H = 6*4

    H=24

    Then, C is:

    C = (3/4) H

    C = (3/4) * 24

    C = 3*24/4

    C=72/4

    C=18

    We can verify it summing C+H

    C+H=24+18=42 verified!
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