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9 May, 03:17

Twenty-four cards are numbered from 1 to 24 and placed in a box. One card is selected at random

and not replaced. Another card is randomly selected. What is the probability of selecting two even

numbers?

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Answers (2)
  1. 9 May, 04:43
    0
    11/46

    Step-by-step explanation:

    between 1 and 24 there are 12 even numbers.

    the probability of selecting an even number the first time is 12/24 = 1/2

    the probability of the second one being an even number without replacement is 11/23

    the probability of both being even numbers without replacement is:

    1/2 * 11/23

    = 11/46
  2. 9 May, 04:57
    0
    11/46

    Step-by-step explanation:

    Given that there are 24 cards numbered 1 - 24

    Even Cards = 2,4,6,8,10,12,14,16,18,20,22,24

    Odd Cards = 1,3,5,7,9,11,13,15,17,19,21,23

    We can see above that in the beginning, we have:

    12 odd and 12 even cards (total of 24 cards)

    If we draw the first card and it is even,

    P (even number on first draw) = 12/24 = 1/2

    If the card is not replaced, now we have:

    12 odd cards and 11 even cards (total of 23 cards)

    If we draw the 2nd card and it is even,

    P (even number on second draw) = 11/23

    Hence probabliliy of drawing the first even card, not replacing and then drawing another even card

    = (1/2) x (11/23)

    = 11/46
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