Problem situation:

Anna is at the movie theater and has $35 to spend.

She spends $9.50 on a ticket and wants to buy some snacks. Each snack costs $3.50.

How many snacks, x, can Anna buy?

Inequality that represents this situation:

9.50+3.50x≤35

Drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution.

Options are:

9 1/2, 3 1/4, 4, 4.25, 2, - 2

Which of these go into Solution to BOTH the inequality and the situation, Solution to the inequality ONLY, and/or NOT a solution

Question

Mathematics

Guest

10 November, 13:55

Problem situation:

Anna is at the movie theater and has $35 to spend.

She spends $9.50 on a ticket and wants to buy some snacks. Each snack costs $3.50.

How many snacks, x, can Anna buy?

Inequality that represents this situation:

9.50+3.50x≤35

Drag each number to show if it is a solution to both the inequality and the problem situation, to the inequality only, or if it is not a solution.

Options are:

9 1/2, 3 1/4, 4, 4.25, 2, - 2

Which of these go into Solution to BOTH the inequality and the situation, Solution to the inequality ONLY, and/or NOT a solution

+5

Answers (2)

Know the Answer?

Brady Hampton · Answer 1

solution to both: 2,4

solution to inequality ONLY: - 2,4.25,3 1/4

Not a solution: 9 1/2

Steven Woods · Answer 2

Anna can buy 7 snacks

Step-by-step explanation:

So if Anna wants to get a a ticket she will have to pay 9.50 so 35-9.50=25.50 and Anna wants to get snacks for x and each snack is 3.50 the 25.50 divided by 3.50 is about 7.29 and with that you cant buy. 29 of a snack so Anna will buy 7 snacks and she will have about 1.02 dollars left (if you needed that)