Ask Question
30 August, 23:55

the heights of students in a class are normally distributed with mean 66 inches and standard deviation 5 inches. Use the Empirical Rule to determine the interval that contains the middle 95% of the eights Q13 a) [61, 71) b) [53, 79 x) [51, 71) Anrme d) O[51, 81 e) [56, 76 f) None of the above

+3
Answers (2)
  1. 31 August, 00:59
    0
    Step-by-step explanation:

    The Empirical rule states that for a normal distribution, nearly all of the data will fall within three standard deviations of the mean. The empirical rule is further illustrated below

    68% of data falls within the first standard deviation from the mean.

    95% fall within two standard deviations.

    99.7% fall within three standard deviations.

    From the information given, the mean is 66 inches and the standard deviation is 5 inches.

    the interval that contains the middle 95% would fall within two standard deviations.

    2 standard deviations = 2 * 5 = 10 inches

    66 - 10 = 56

    66 + 10 = 76

    Therefore, interval that contains the middle 95% is between 56 and 76 inches
  2. 31 August, 03:10
    0
    e) [56, 76]

    Step-by-step explanation:

    The Empirical rule states that, for a normally distributed random variable:

    68% of the measures are within 1 standard deviation of the mean. Those are called the middle 68%.

    95% of the measures are within 2 standard deviations of the mean. Those are called the middle 95%.

    99.7% of the measures are within 3 standard deviation of the mean. Those are called the middle 99.7%.

    In this problem, we have that:

    Mean 66, standard deviation 5

    So the middle 95% is:

    From 66 - 2*5 = 56 to 66 + 2*5 = 76

    So the correct answer is:

    e) [56, 76]
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “the heights of students in a class are normally distributed with mean 66 inches and standard deviation 5 inches. Use the Empirical Rule to ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers