You own three different rings. You wear all three rings, but no two of the rings are on the same finger, nor are any of them on your thumbs. In how many ways can you wear your rings? (Assume any ring will fit on any finger.) Explain and prove your answer.

Question

Mathematics

Guest

7 March, 06:04

You own three different rings. You wear all three rings, but no two of the rings are on the same finger, nor are any of them on your thumbs. In how many ways can you wear your rings? (Assume any ring will fit on any finger.) Explain and prove your answer.

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Answers (1)

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Kendal · Answer 1

Therefore you can wear your rings in = 336 ways

Step-by-step explanation:

Multiplication Law: If one occurs in x ways and second event occurs in y ways. Then the number of ways that two event occur in sequence is xy

Given that you have 3 different rings.

We have total 10 figures.

But you don't wear ring on your thumbs.

We have 2 thumbs.

So you can wear rings on (10-2) = 8 figures.

The ways of wearing of first ring is = 8

The ways of wearing of second ring is = 7

The ways of wearing of third ring is = 6

Therefore you can wear your rings in = (8*7*6)

=336 ways