Let y = safe load in pounds and x = length in feet of a horizontal beam. A constant of proportionality k exists such that. If a beam can hold 2,000 pounds at 15 feet, what maximum length should be used to safely support 500 pounds? 6 feet 60 feet 150 feet

60feets

Step-by-step explanation:

The question is incomplete. The complete question is "Let y = safe load in pounds and x = length in feet of a horizontal beam. A constant of proportionality k exists such that y = k/x. If a beam can hold 2,000 pounds at 15 feet, what maximum length should be used to safely support 500 pounds"

Since y = k/x

k = xy

If a beam can hold 2,000 pounds at 15 feet, x = 15ft y = 2000pounds

K = 15*2000

k = 30,000

To get the maximum length that should be used to safely support 500 pounds, we will use the relationship k = xy where y = 500pounds, k = 30000

x = k/y

x = 30000/500

x = 60feets

The maximum length that should be used to safely support 500 pounds is 60feets