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22 April, 12:59

Neglecting air resistance, the distance s (t) in feet traveled by a freely falling object is given by the function s (t) = 16t squared , where t is time in seconds. The height of a certain tower is 986 feet. How long would it take an object to fall to the ground from the top of the building?

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  1. 22 April, 13:43
    0
    Answer: t = 7.85seconds

    Step-by-step explanation:

    Given that:

    Height of tower = 986 Feets

    Function s (t) = 16t^2

    To find the time t 8 in Seconds taken for an object to fall to the ground from the top of the building

    16t^2 = 986

    t^2 = 986/16

    t ^2 = 61.625

    Take the square root of both sides

    t = sqrt (61.625)

    t = 7.85seconds
  2. 22 April, 14:54
    0
    7.85sec

    Step-by-step explanation:

    Given that,

    s (t) = 16t squared , where t is time in seconds. The height of a certain tower is 986 feet.

    s (t) = 16t²

    so when s = 986feet

    16t² = 986 feet

    t² = 986 / 16

    t² = 61.625

    t = √61.625

    t = 7.85 seconds
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