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Yesterday, 14:41

Tanya kicks a ball into the air. The function that models this is f (t) = - 16t^2 + 96t, where h is the height of the ball in feet and t is the time seconds

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  1. Yesterday, 15:46
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    The question is incomplete. The complete question is here.

    Tanya kicks a ball into the air. The function that models this scenario is h (t) = - 16t² + 96t, where h is the height of the ball in feet and t is the time seconds. When will the ball hit the ground?

    Answer:

    The ball will hit the ground after 6 seconds

    Step-by-step explanation:

    ∵ h (t) = - 16t² + 96t

    ∵ h is the height of the ball in feet for t seconds

    - That means at the ground h = 0

    ∵ h (t) = 0 when the ball hit the ground

    ∴ 0 = - 16t² + 96t

    Let us solve it by adding 16t² to both sides

    ∴ 16t² = 96t

    - Subtract 96t from both sides

    ∴ 16t² - 96t = 0

    Factorize it by taking 16t as a common factor from each term

    ∵ 16t² : 16t = t

    ∵ 96t : 16t = 6

    ∴ 16t (t - 6) = 0

    Equate each factor by 0

    ∵ 16t = 0

    - Divide both sides by 16

    ∴ t = 0 ⇒ initial position

    ∵ t - 6 = 0

    - Add 6 to both sides

    ∴ t = 6 ⇒ final position

    ∴ The ball will hit the ground after 6 seconds
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