Suppose a basketball team had a season of games with the following characteristics: Of all the games, 60% were at-home games. Denote this by H (the remaining were away games). Of all the games, 25% were wins. Denote this by W (the remaining were losses). Of all the games, 20% were at-home wins. Of the at-home games, we are interested in finding what proportion were wins. Which of the following probabilities do you need to find in order to determine the proportion of at-home games that were wins?

A. P (H)

B. P (W)

C. P (H and W)

D. P (H | W)

E. P (W | H)

Question

Mathematics

Yoselin Raymond

10 July, 12:29

Suppose a basketball team had a season of games with the following characteristics: Of all the games, 60% were at-home games. Denote this by H (the remaining were away games). Of all the games, 25% were wins. Denote this by W (the remaining were losses). Of all the games, 20% were at-home wins. Of the at-home games, we are interested in finding what proportion were wins. Which of the following probabilities do you need to find in order to determine the proportion of at-home games that were wins?

A. P (H)

B. P (W)

C. P (H and W)

D. P (H | W)

E. P (W | H)

+3

Answers (1)

Know the Answer?

Abdullah Mora · Answer 1

E. P (W | H).

Step-by-step explanation:

We are given that 60% are at-home games. So,

P (H) = 0.60.

We are given that 25% are winning games. So,

P (W) = 0.25.

We are given that 20% are at-home winning games. So,

P (H and W) = 0.20.

We are interested in finding what proportion of at-home games wins. So, we want are given that basketball team had a home game and we want to find win games. So, we are interested in finding probability of win given that a game is at-home game. Thus, we want to determine P (W|H).

Further, P (W|H) can be determine with the given information as

P (W|H) = P (W and H) / P (H)

P (W|H) = 0.2/0.6

P (W|H) = 0.333.