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15 June, 00:43

If M is a two digit number and N is obtained by reversing M, if M+N = 132, how many values can M have?

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  1. 15 June, 01:44
    0
    7

    Step-by-step explanation:

    Let M be a two digit number with x in the tens position and y in units:

    M = 10x + y

    Then N will have y in the tens position and x in units:

    N = 10y + x

    M+N = 10x + y + 10 + x = 132

    11x + 11y = 132

    11 (x + y) = 132

    x + y = 12

    x and y are single digit whole numbers. Possible combinations are:

    x = 3 y = 9

    x = 4 y = 8

    x = 5 y = 7

    x = 6 y = 6

    x = 7 y = 5

    x = 8 y = 4

    x = 9 y = 3

    Values of M can be:

    39, 48, 57, 66, 75, 84, 93

    Which are 7
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