Mrs. Mott called two companies about getting new uniforms for the soccer team. The first company she called charges $70 per uniform. The second company she called charges $280plus $30 per uniform. For how many uniforms will the cost from the first company be less expensive than the cost from the second company?

Question

Mathematics

Lilianna Heath

4 July, 03:45

Mrs. Mott called two companies about getting new uniforms for the soccer team. The first company she called charges $70 per uniform. The second company she called charges $280plus $30 per uniform. For how many uniforms will the cost from the first company be less expensive than the cost from the second company?

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Answers (1)

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Finnegan Landry · Answer 1

For less than 7 uniforms.

Step-by-step explanation:

The first company she called charges $70 per uniform.

So, the cost of x uniforms will be $70x.

The second company she called charges $280 plus $30 per uniform.

So, the cost of x uniform will be $ (280 + 30x).

Now, if the total cost of purchasing x number of uniforms from the first company is less than that from the second company then, we can write the inequality equation as

70x < 280 + 30x

⇒ 70x - 30x < 280

⇒ 40x < 280

⇒ x < 7

Therefore, for less than 7 uniforms the cost from the first company will be less than the cost from the second company. (Answer)