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Mathematics
Ayla
6 June, 05:48
How do i solve 5x+3y=-10 & 3x+5y=-6
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Bryant Kerr
6 June, 07:46
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Solve it using elimination method:
5x+3y=-10
3x+5y=-6
Essentially what you would want to do is eliminate a variable so you have to multiply the two equations so that the two "y"s cancel each other out. You do this by multiplying one by a negative number and the other one a positive number. Doesn't matter what number you multiply the number with; however, both numbers need to be the same distance away from zero. Also, if you're going to multiply one term, then all the terms will need to be multiplied.
-5 (5x+3y) = -10
3 (3x+5y) = -6
Distribute and Multiply:
-25x-15y=50
9x+15y=-18
Now add the two equations by adding the x's together, y's, and the total.
The y's end up canceling each other.
-16x=32
Divide:
X=-2
Now that you have "X" substitute x from one of the equations from the beginning. You may do two for checking answers.
3 (-2) + 5y=-6
-6+5y=-6
5y=0
Y=0
The answer is:
x=-2
y=0
(-2,0)
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