Ask Question
21 February, 20:40

An archer hits a bull's-eye with a probability of 0.09, and the results of different attempts can be taken to be independent of each other. If the archer shoots nine arrows, what is the variance of the number of bull's-eyes scored?

+2
Answers (1)
  1. 21 February, 23:03
    0
    Answer: Variance = 0.858

    Step-by-step explanation: The variance formulae for a probability distribution is given below as

    Variance = √npq

    Where n = number of times experiment was performed = 9

    p = probability of success = 0.09

    q = probability of failure = 1 - p = 1 - 0.09 = 0.91

    Variance = √9*0.09*0.91

    Variance = √0.7371

    Variance = 0.858
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “An archer hits a bull's-eye with a probability of 0.09, and the results of different attempts can be taken to be independent of each other. ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers