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7 July, 21:17

Two buses leave towns 1015 miles apart at the same time and travel toward each other. One bus travels 11 miles/hr slower than the other. If they meet in 7 hours, what is the rate of each bus?

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  1. 8 July, 00:12
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    Step-by-step explanation:

    Bus One

    speed = x

    t = 7 hours

    d = ?

    Bus two

    speed = x + 11

    time = 7 hours

    d1 = 1015 miles - d

    Equations

    d = s * t

    Bus 1 + bus 2 = 1015

    Solution

    x * 7 + (x + 11) * 7 = 1015

    7x + 7x + 11*7 = 1015

    14x + 77 = 1015

    14x + 77 - 77 = 1015 - 77

    14x = 938

    14x/14 = 938/14

    x = 67 miles / hour

    x + 11 = 78 miles / hour
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