Explain how to solve 4|3x-1|+1=8

4|3x - 1| + 1 = 8

4|3x - 1| = 8 - 1

4|3x - 1| = 7

|3x - 1| = 7/4

Now lets think, we have 3x - 1 in module, so either its 7/4 or - 7/4, we will have 7/4 at the end because of it, so we may have 2 solutions in this case:

3x - 1 = 7/4

and

3x - 1 = - 7/4

So let's see:

3x - 1 = 7/4

3x = 7/4 + 1

3x = 11/4

x = 11/12

3x - 1 = - 7/4

3x = - 7/4 + 1

3x = - 3/4

x = - 1/4

So we have two possible answers, x = 11/2 and x = - 1/4