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18 May, 14:10

In Canada, households spent an average of $80.63 CDN monthly for high-speed broadband access. 24 Assume that the standard deviation is $27.32. If you ask an SRS of 500 Canadian households with high-speed broadband access how much they pay, what is the probability that the average amount will exceed $85?

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  1. 18 May, 14:33
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    Step-by-step explanation:

    Assuming a normal distribution for the amount spent by Canadian households for high-speed broadband access, the formula for normal distribution is expressed as

    z = (x - u) / s

    Where

    x = amount spent by the Canadian households.

    u = mean amount spent monthly.

    s = standard deviation

    From the information given,

    u = $80.63 CDN

    s = $27.32 CDN

    We want to find the probability that the average amount will exceed $85. It is expressed as

    P (x greater than 85) = 1 - P (x lesser than or equal to 85)

    For x = 85

    z = (85 - 80) / 27.32 = 0.18

    Looking at the normal distribution table, the corresponding z score is 0.57142

    P (x greater than 85) = 1 - 0.57142 = 0.43
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