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24 November, 14:51

Suppose that E and F are two events and that Upper N (Upper E and Upper F) N (E and F) equals=250250 and Upper N (Upper E) N (E) equals=560560. What is Upper P (F|E) P (F|E) ?

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  1. 24 November, 17:05
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    the probability is 0.4642 (46.42%)

    Step-by-step explanation:

    for the events E and F such that

    N (E ∩ F) = 250 and N (E) = 560

    where N represents the number of elements in that set, we can use the theorem of Bayes for conditional probability. Then representing N total = N (E∪F), we have that the probability is

    P (F|E) = P (E ∩ F) / P (E) = [N (E ∩ F) / N total] / [N (E) / N total ] = N (E ∩ F) / N (E) = 250/560 = 0.4642 (46.42%)
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