Ask Question
6 September, 03:19

An experiment was conducted at a small supermarket for a period of 8 days on the sales of a single brand of dog food, involving three levels of shelf height: knee level, waist level, and eye level. During each day, the shelf height of the dog food was randomly changed on three different occasions. Sales, in hundreds of dollars, of the dog food per day for the three shelf heights are given below. Based on the data, is there a significant difference in the average daily sales of this dog food based on shelf height? Use a 0.05 level of significance. Shelf Height Knee Level Waist Level Eye Level 77 88 85 82 94 85 86 93 87 78 90 81 81 91 80 86 94 79 77 90 87 81 87 93

+4
Answers (1)
  1. 6 September, 03:59
    0
    There is no significant difference in the average daily sales of this dog food based on shelf height

    Step-by-step explanation:

    Null hypothesis: There is no significant difference in the average sales

    Alternate hypothesis: There is a significant difference in the average daily sales

    Using the F-table, at 0.05 significance level and (2, 21) degrees of freedom (3-1, 24-3), the critical value is 3.47

    Conclusion: Reject the null hypothesis if the computed F exceeds 3.47

    Data values

    Knee level: 77,88,85,82,94,85,86,93 (Mean is 86.25)

    Waist level: 87,78,90,81,81,91,80,86 (Mean is 84.25)

    Eye level: 94,79,77,90,87,81,87,93 (Mean is 86)

    Grand mean = (86.25+84.25+86) / 3 = 85.5

    Sum of Squares (SS) for knee level = summation (sales - grand mean) ^2 = 220

    SS for waist level = 180

    SS for eye level = 288

    SStotal = 220+180+288 = 688

    Sum of Squares due to Treatment (SST) for knee level = n (mean - grand mean) ^2 = 8 (86.25 - 85.5) ^2 = 4.5

    SST for waist level = 12.5

    SST for eye level = 0.25

    Total SST = 4.5+12.5+0.25 =

    17.25

    Mean Sum of Treatment (MST) = SST / (number of food types - 1) = 17.25 / (3-1) = 17.25/2 = 8.625

    Sum of Squares due to Error (SSE) = SStotal - SST = 688 - 17.25 = 670.75

    Mean Sum of Error (MSE) = SSE / (24-3) = 670.75/21 = 31.940

    F = MST/MSE = 8.625/31.940 = 0.27

    The computed F 0.27 is less than the critical value 3.47, so we fail to reject the null hypothesis

    Conclusion: There is no significant difference in the average daily sales of this dog food based on shelf height
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “An experiment was conducted at a small supermarket for a period of 8 days on the sales of a single brand of dog food, involving three ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers