Ask Question
18 September, 20:56

Write the radius of the circle x2 + y2 + 5x - 4y = 0.

square root (29)

square root (417/2)

square root (41)

+3
Answers (1)
  1. 19 September, 00:20
    0
    r = √41

    Step-by-step explanation:

    recall that the general equation of a circle (in center-radius form) looks like

    (x-h) ² + (y-k) ² = r²

    where, r is the radius of the circle.

    however we are given the general 2nd degree form:

    x² + y² + 5x - 4y = 0

    in order to convert this to the center radius form, we have to complete the square for x and y simultaneously:

    x² + y² + 5x - 4y = 0 (rearrange)

    x² + 5x + y² - 4y = 0 (group x and y terms)

    (x² + 5x) + (y² - 4y) = 0 (complete the square)

    [x² + 5x + (5/2) ² ] + [y² - 4y + (-4/2) ² ] = (5/2) ² + (-4/2) ² (simplify)

    [x + (5/2) ]² + [y - (4/2) ] ² = 25/4 + 4

    [x + (5/2) ]² + [y - 2] ² = 25/4 + 4

    [x + (5/2) ]² + [y - 2] ² = 41

    [x + (5/2) ]² + [y - 2] ² = (√41) ²

    if we compare this equation with the general equation above, we can clearly see that r = √41
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “Write the radius of the circle x2 + y2 + 5x - 4y = 0. square root (29) square root (417/2) square root (41) ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers