A ball is kicked from ground level with a velocity of 20 m/s at 30 degrees above the horizontal. Determine the horizontal displacement to where it lands and find how high the ball went at max height.

Answer:the horizontal displacement is 34.64 meters

The maximum height is 15 meters

Step-by-step explanation:

As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range, R is

R = U^2Sin2#) / g

Where

U represents the initial velocity of the ball

g is acceleration due to gravity

# represents the angle above the horizontal.

From the information given

# = 30 degrees

U = 20 m/s

g = 10m/s^2

R = 20^2Sin2*30) / 10 = (400Sin60) / 20 = (400*0.8660) / 10

= 34.64 meters

To determine the maximum height of the ball, H,

H = (U^2Sin^2#) / 2g

H = (20^2 * Sin^2 30) / 2*10

H = (400 * 0.866^2) / 20 = 15 meters