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27 February, 21:05

How many numbers of at mose three different digits can be formed from the integer 1,2,3,4,5,6.

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Answers (2)
  1. 27 February, 21:33
    0
    156 numbers

    Step-by-step explanation:

    If the digits have to be at most 3, then we have 3, 2 and 1 digit.

    using permutation n! / (n-k) !

    Where n is no of objects

    k is no to be used

    For 3, 6! / (6-3) !

    6*5*4*3*2*1/3*2*1 = 120

    For 2,

    6! / (6-2) !

    6*5*4*3*2*1/4*3*2*1 = 30

    For 1,

    6! / (6-1) !

    6*5*4*3*2*1/5*4*3*2*1 = 6

    Total, 120 + 30 + 6 = 156
  2. 27 February, 23:52
    0
    The answer is 1920, right? Here is how-

    The numbers must contain at least three digit and can go above that which means the answer has 3 4 5 and 6 digits all together.

    For three digits, there will be 6*5*4 = 120

    For 4 Digits, There will be 6*5*4*3=360 possible numbers

    For 5 digits, there will be 6*5*4*3*2 = 6! = 720

    For 6 digits, there will be 6*5*4*3*2*1 = 6! = 720

    Now add them up = 120+360+2*720 = 1920
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