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9 June, 21:03

1. Popeye is lifting Olive Oyl off the ground by pulling her upward with a force of 108.1 N. She is pretty thin so she only weighs 10 kg. What is Olive Oyl's acceleration as a result of this force?

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Answers (2)
  1. 9 June, 22:03
    0
    1.01 m/s²

    Step-by-step explanation:

    From Newton's law of motion,

    ma = F-W ... Equation 1

    Where m = mass of Olive Oyl, a = acceleration, F = Upward force, W = weight of Olive Oyl.

    Also,

    W = mg ... Equation 2

    Where g = acceleration due to gravity.

    Substitute equation 2 into equation 1

    ma = F-mg

    make a the subject of the equation

    a = (F-mg) / m ... Equation 3

    Given: F = 108.1 N, m = 10 kg

    Constant: g = 9.8 m/s²

    Substitute into equation 3

    a = [108.1 - (10*9.8) ]/10

    a = (108.1-98) / 10

    a = 10.1/10

    a = 1.01 m/s²

    Hence, Olive Oyl's acceleration = 1.01 m/s²
  2. 9 June, 23:28
    0
    1 m/s2

    Step-by-step explanation:

    Olive Oyl's weight = 10 * 9.81 = 98.1 N

    This weight is a force acting downward because it is due to gravity.

    Popeye pulls Olive Oyl up with a force of 108.1 N. Both forces act vertically but in opposite directions. Hence their resultant, R, is their difference and is in the direction of the larger force.

    R = 108.1 N - 98.1 N = 10 N

    This force causes an acceleration, a, on the mass, m, of Popeye.

    R = ma

    a = R/m = 10 N/10 kg = 1 m/s2
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