16 April, 14:40
X²+y²=25 xy=12 find the value of (3x+3y) ²
16 April, 16:29
(a + b) ²=a²+2ab+b²
(3x+3y) ² = (3x) ²+2*3x*3y + (3y) ²
=9x² + 18xy + 9y²
=9x² + 9y² + 18xy
= 9 * (x²+y²) + 18xy
=9*25 + 18*12
=225 + 216
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» X²+y²=25 xy=12 find the value of (3x+3y) ²