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18 May, 14:10

Evaluate log base 12 of y^2, given log base 12=16

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  1. 18 May, 14:43
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    y = 12^8

    Step-by-step explanation:

    Log base 12, y^2 = 16

    y2 = 12^16

    y = sqrt (12^16) = (12^16) ^1/2

    y = 12^8
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