Ask Question
24 February, 03:20

A fish tank holds 832 gallons but is leaking at a rate of 5 gallons per week. A second fish tank hose 1040 gallons but is leaking any rate of 9 gallons per week after how many weeks with the amount of water in the two fish tanks me the same

+3
Answers (1)
  1. 24 February, 06:52
    0
    Within 52 weeks, the amount of water in the two fish tanks will be the same.

    Step-by-step explanation:

    First, let's make the two equations equal to each other by placing an equal sign.

    832 - 5x = 1040 - 9x

    Now, that they are equal to each other, we can solve for x.

    Okay, so we can move - 5x to the other side by adding both sides with 5x.

    832 = 1040 - 4x

    Then, subtract 1040 from both sides to move it to the other side.

    832 - 1040 = - 208

    -208 = - 4x

    Lastly, divide both sides by - 4 to get the value of x.

    -208/-4 = 52

    x = 52
Know the Answer?
Not Sure About the Answer?
Get an answer to your question ✅ “A fish tank holds 832 gallons but is leaking at a rate of 5 gallons per week. A second fish tank hose 1040 gallons but is leaking any rate ...” in 📙 Mathematics if there is no answer or all answers are wrong, use a search bar and try to find the answer among similar questions.
Search for Other Answers