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21 September, 11:58

An exam consists of 47 multiple-choice questions. Each question has a choice of five answers, only one of which is correct. For each correct answer, a candidate gets 1 mark, and no penalty is applied for getting an incorrect answer. A particular candidate answers each question purely by guess-work. Using Normal approximation to Binomial distribution with continuity correction, what is the estimated probability this student obtains a score greater than or equal to 10?

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  1. 21 September, 12:46
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    0.0160

    Step-by-step explanation:

    P = 1/5

    Q = 4/5

    Mean = np

    Standard deviation = √npq

    P (9
    n = 47

    Mean = 47 * 1/5 = 9.4

    Standard deviation = √9.5 * 4/5)

    = 2.75

    = P (9.5-9.4) / 2.74 < z

    = P (0.1/2.74) < z

    = P (z < 0.036)

    = 0.0160.
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