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16 March, 20:14

Evaluate Ic2 + b2l, given a = 5, b = - 3, and c = - 2.

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  1. 16 March, 20:27
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    Ic² + b²l = 13 units.

    Step-by-step explanation:

    We have to evaluate the expression Ic² + b²l with unknowns b and c and having the values of b and c respectively - 3 and - 2.

    Now, Ic² + b²l

    = I ( - 2) ² + ( - 3) ²l {Putting the values of b and c}

    = I4 + 9l

    = I13l

    = 13 units.

    Therefore, Ic² + b²l = 13 units. (Answer)
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