The mean number of daily surgeries at a local hospital is 6.2. Assume that surgeries are random, independent events.

(a) The count of daily surgeries follows approximately:

A Poisson distribution with mean 6.2 and standard deviation 2.49.

A binomial distribution with mean 6.2 and standard deviation 3.8.

A binomial distribution with mean 6.2 and standard deviation 1.76.

A Poisson distribution with mean 6.2 and standard deviation 6.2.

A binomial distribution with mean 6.2 and standard deviation 3.1.

Question

Mathematics

Franco Bradshaw

30 November, 06:28

The mean number of daily surgeries at a local hospital is 6.2. Assume that surgeries are random, independent events.

(a) The count of daily surgeries follows approximately:

A Poisson distribution with mean 6.2 and standard deviation 2.49.

A binomial distribution with mean 6.2 and standard deviation 3.8.

A binomial distribution with mean 6.2 and standard deviation 1.76.

A Poisson distribution with mean 6.2 and standard deviation 6.2.

A binomial distribution with mean 6.2 and standard deviation 3.1.

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Answers (1)

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Sage Cohen · Answer 1

The count of daily surgeries follows approximately a Poisson distribution with mean 6.2 and standard deviation 2.49.

Step-by-step explanation:

The Poisson distribution is a discrete probability distribution that expresses the probability of a certain number of events occurring during a certain period of time.

In this exercise the period of time is daily.

The mean of the distribution is λ=6.2.

The standard deviation of the distribution is √λ=√6.2=2.49