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Mathematics
Philip Haney
6 May, 21:38
What are the factors of 5y^2-2y-7
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Darian Kim
6 May, 22:13
0
Answer:7/5, - 1
Step-by-step explanation:
all quadratic equations have 2 roots so meaning it is factorized into to bracts so first step
(5y) (y)
the reason there is a five before one of the y's is because the a in our function {ax^2+bx+c}
second step is to factorize so u think what 2 numbers are equal to - 7 when multiplied. since 7 is a prime number its either 7 and - 1 or - 7 and 1
so u try both factors to check the middle term
first one
(5y+7) (y-1)
that would be equal to 5y^2+2y-7 which isn't the function we are looking for therefore the
second one (5y-7) (y+1)
that would be equal to 5y^2-2y-7 which is correct
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Kaleigh Garrett
6 May, 22:46
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The correct answer is 7/5 and - 1
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