Yulet rolls 2 fair dice and adds the results from each. Work out the probability of getting a total of 7.

the answer is 1/6

Step-by-step explanation:

Let (a, b) denote a possible outcome of rolling the two die, with a the number on the top of the first die and b the number on the top of the second die. Note that each of a and b can be any of the integers from 1 through 6. Here is a listing of all the joint possibilities for (a, b):

(1,1) (1,2) (1,3) (1,4) (1,5) (1,6)

(2,1) (2,2) (2,3) (2,4) (2,5) (2,6)

(3,1) (3,2) (3,3) (3,4) (3,5) (3,6)

(4,1) (4,2) (4,3) (4,4) (4,5) (4,6)

(5,1) (5,2) (5,3) (5,4) (5,5) (5,6)

(6,1) (6,2) (6,3) (6,4) (6,5) (6,6)

With the above declaration, the outcomes where the sum of the two dice is equal to 7 form an event. If we call this event E, we have

E={ (1,6), (2,5), (3,4), (4,3), (5,2), (6,1) }.

so Possibilities (P) of having Event (E)

P (E) = 6/36

= 1/6