Hooke's Law says that the force exerted by the spring in a spring scale varies directly with the distance that the spring is stretched. If a 32 pound mass suspended on a spring scale stretches the spring 11 inches, how far will a 43 pound mass stretch the spring? (Round off your answer to 1 decimal place.)

Answer:the spring would be stretched 14.8 inches.

Step-by-step explanation:

Hooke's Law says that the force exerted by the spring in a spring scale varies directly with the distance that the spring is stretched.

If the force is F and the distance that the spring is stretched is e, then

F is directly proportional to e

Introducing a proportionality constant, k it becomes.

F = ke

If a 32 pound mass suspended on a spring scale stretches the spring 11 inches, it means that

32 = k * 11

k = 32/11

The expression becomes

F = 32e/11

If a 43 pound mass spring is stretched, then,

43 = 32e/11

32e = 43 * 11 = 473

e = 473/32 = 14.8 inches

14.776 inches

Step-by-step explanation:

32 pound mass stretches the spring by 11 inches,

where F = ke where k is a constant and e is the extension

32/11 = k

k = 2.91

then 43 pound will stretch it by

f = ke

43 / 2.91 = e in inches

e = 14.776 inches