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23 January, 19:58

How would I solve for slope on an equation similar to 8x+2y=5?

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  1. 23 January, 20:06
    0
    Well make the equation into slope intercept form: y=mx + b and whatever the coefficent is to x will be your slope

    8x+2y = 5 can be written as y = (-8/2) x + (5/2) so the slope would be (-8/2)
  2. 23 January, 20:32
    0
    You would isolate the y-value: 2y=5-8x and simplify into y=-4x+2.5 and that means that the slope is - 4
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