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30 March, 17:26

A menu offers a choice of 2 salads, 6 main dishes, and 5 desserts. How many different meals consisting of one salad, one main dish, and one dessert are possible?

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  1. 30 March, 17:42
    0
    60 different meals

    Step-by-step explanation:

    The possibilities of 1 salad = 2

    The possibilities of 1 main dishes = 6

    The possibilities of 1 desert = 5

    Then we multiply all the types of posibilities together in other to have different meals consisting of one salad, one main dish, and one dessert

    2*5*6 = 60

    Cheers
  2. 30 March, 18:10
    0
    Answer is 60

    Step-by-step explanation:

    The possibility of a salad meal is = 2

    2C1 = 2

    The possibility of a main dish = 6

    6C1 = 6

    The possibility of a dessert is = 5

    5C1 = 5

    So the total possibility is the multiplication of the three i. e

    2*6*5 = 60

    The principle applied is the combination principle.

    Note that C stands for combination
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